题目：

Find the total area covered by two rectilinear rectangles in a 2D plane.

Each rectangle is defined by its bottom left corner and top right corner as shown in the figure.

 

Assume that the total area is never beyond the maximum possible value of int.

答案：

没什么好说的，两个矩形相加，如果有重合部分则减去重合部分的面积

 

1 class Solution { 2 public: 3     int computeArea(int A, int B, int C, int D, int E, int F, int G, int H) { 4         int sum; 5         sum=(C-A)*(D-B)+(G-E)*(H-F); 6         if(E>=C||F>=D||B>=H||A>=G){ 7             return sum; 8         } 9         else{10             int overlap;11             overlap=(min(C,G)-max(E,A))*(min(D,H)-max(B,F));12             return (sum-overlap);13         }14     }15 };